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Chapter 6: Problem 48

Looking to cut costs, the airline you work for asks you to investigate the efficiency of the tractors that push aircraft away from the gates. One model is supposed to do no more than 10 MJ of work in pushing a 747 aircraft \(25 \mathrm{m}\). If the tractor exerts a \(0.42-\mathrm{MN}\) force, does it meet its specifications?

Short Answer

Expert verified
No, the tractor does not meet its specifications as the work done (10.5 MJ) is greater than the specified maximum work (10 MJ).

Step by step solution

01

Convert Force Unit

First, let's convert the force from meganewtons (MN) to newtons (N) since the standard unit of force in International System of Units (SI) is newton. 1 MN = \(10^6\) N. So, the force exerted by the tractor is \(0.42 * 10^6\) N = \(420000 N\).
02

Calculate Work Done

The formula to calculate work is Work = Force x Distance. So, substitute the values into the formula: Work = \(420000N * 25m = 10500000 J\)
03

Convert Work Done to MJ and Compare

The work done should not exceed 10MJ. Convert the work done from J to MJ by dividing by \(10^6: 10500000J/10^6 = 10.5 MJ\). Now, compare the work done with the specified maximum work. Since 10.5 MJ is greater than the 10 MJ specified by the airline, the tractor does not meet its specifications.

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