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Chapter 1: Problem 116

At what atmospheric pressure will water boil at \(35^{\circ} \mathrm{C} ?\) Express your answer in both SI and BG units.

Short Answer

Expert verified
The pressure at which water will boil at 35-degrees Celsius is 130.667 atmospheres, which is also equal to 13236131.67 Pascal or 1921.987 PSI.

Step by step solution

01

Conversion of Celsius to Kelvin

First, we need to convert the given temperature of 35-degree Celsius to Kelvin as the equation works in Kelvin. This can be done by the formula: \( K = C + 273.15 \). Here, \( K \) represents degrees Kelvin. \( C \) represents degrees Celsius. Hence, for 35-degree Celsius, \( K = 35 + 273.15 = 308.15 K \).
02

Applying Antoine equation

Now, we can apply Antony's equation to find the pressure. logP = 8.07131 - (1730.63 / (308.15 + 233.426)), using log as natural log since we want to find pressure in atmospheres. Solving it further gives us logP = 8.07131 - (1730.63 / 541.576) = 8.07131 - 3.19443 = 4.876. Exponentiating both sides, we get, \( P = e^{4.876} = 130.667 atm. \) This is the pressure in atmospheres.
03

Conversion to SI and BG units

Finally, we need to convert the pressure from atmospheres to Pascal and PSI. To convert atm to Pa, we use the conversion factor 101325, i.e., 1 atm = 101325 Pa. Thus, \(130.667 atm = 130.667 * 101325 = 13236131.67 Pascal \). And to convert atm to PSI, we use the conversion factor 14.696, i.e., 1 atm = 14.696 PSI. Thus, \( 130.667 atm = 130.667 * 14.696 = 1921.987 PSI \).

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Most popular questions from this chapter

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