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Chapter 1: Problem 122

A method used to determine the surface tension of a liquid is to determine the force necessary to raise a wire ring through the air-liquid interface. What is the value of the surface tension if a force of \(0.015 \mathrm{N}\) is required to raise a 4 -cm-diameter ring? Consider the ring weightless, as a tensiometer (used to measure the surface tension) "zeroes" out the ring weight.

Short Answer

Expert verified
The surface tension is \(0.02 N.m^{-1}\)

Step by step solution

01

List down the known values

The force \(F\) required to raise the ring is given, which is \(0.015 N\), and the diameter \(d\) of the wire ring is \(4 cm\) or \(0.04 m\). Constants include \(\pi = 3.14159\).
02

Use the formula of surface tension

Surface tension \(\gamma\) is given by the formula \(\gamma = \frac{F}{2\pi d}\). Substitute the known values into the formula.
03

Calculate surface tension

Substituting the values, we get \(\gamma = \frac{0.015N}{2*3.14159*0.04m} = 0.02 N.m^{-1}\).

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