The density of a certain type of jet fuel is $775 \mathrm{kg} / \mathrm{m}^{3}$. Determine its specific gravity and specific weight.

Short Answer

Expert verified
The specific gravity of the jet fuel is 0.775 while its specific weight is 7601.75 N/m³.

Step by step solution

01

Calculate specific gravity

To calculate specific gravity, divide the density of the fluid (jet fuel in this case) by the density of water: Specific gravity = \(\frac{density of fluid}{density of water}\) This gives: Specific gravity = \(\frac{775 kg/m^3}{1000 kg/m^3}\) = 0.775. Therefore, the specific gravity of the jet fuel is 0.775.
02

Calculate specific weight

Specific weight is computed by multiplying the density of the fluid with the acceleration due to gravity. The formula is Specific weight = density of fluid x acceleration due to gravity This gives: Specific weight = 775 kg/m³ x 9.81 m/s² = 7601.75 N/m³ (since 1N = 1kg.m/s²) Therefore, the specific weight of the jet fuel is 7601.75 N/m³.

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