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Chapter 1: Problem 59

The viscosity of a certain fluid is \(5 \times 10^{-4}\) pcise. Determine its viscosity in both SI and BG units.

Short Answer

Expert verified
The viscosity of the fluid in SI units is \(5 \times 10^{-5} \) Pa.s and in BG units is \(3.36 \times 10^{-7}\) lb/ft/s.

Step by step solution

01

Converting viscosity from poise (P) to Pascal second (Pa.s)

1 poise (P) is equivalent to 0.1 Pascal second (Pa.s). So, it can be converted by multiplying the viscosity in poise by 0.1. So, the viscosity will be \(5 \times 10^{-4} \) * 0.1 = \(5 \times 10^{-5} \) Pa.s.
02

Converting viscosity from poise (P) to British Gravitational (BG) units

1 poise (P) is equivalent to 6.72 * 10^-4 lb/ft/s. So, it can be converted by multiplying the viscosity in poise by 6.72 * 10^-4. So, the viscosity will be \(5 \times 10^{-4} \) * 6.72 * \(10^-4\) = \(3.36 \times 10^{-7}\) lb/ft/s.

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Most popular questions from this chapter

For a parallel plate arrangement of the type shown in Fig. 1.5 it is found that when the distance between plates is \(2 \mathrm{mm}\), a shearing stress of 150 Pa develops at the upper plate when it is pulled at a velocity of \(1 \mathrm{m} / \mathrm{s}\). Determine the viscosity of the fluid between the plates. Express your answer in SI units.

One type of capillary-tube viscometer is shown in Video V1.5 and in Fig. P1.57. For this device the liquid to be tested is drawn into the tube to a level above the top etched line. The time is then obtained for the liquid to drain to the bottom etched line.The kinematic viscosity, \(\nu,\) in \(\mathrm{m}^{2} / \mathrm{s}\) is then obtained from the equation \(\nu=K R^{4} t\) where \(K\) is a constant, \(R\) is the radius cf the capillary tube in \(\mathrm{mm}\), and \(t\) is the drain time in seconds. When glycerin at \(20^{\circ} \mathrm{C}\) is used as a calibration fluid in a particular viscometer, the drain time is 1430 s. When a liquid having a density of \(970 \mathrm{kg} / \mathrm{m}^{3}\) is tested in the same viscometer the drain time is 900 s. What is the dynamic viscosity of this liquid?

The kinematic viscosity and specific gravity of a liquid are \(3.5 \times 10^{-4} \mathrm{m}^{2} / \mathrm{s}\) and \(0.79,\) respectively. What is the dynamic viscosity of the liquid in SI units?

A compressed air tank in a service station has a volume of \(10 \mathrm{ft}^{3} .\) It contains air at \(70^{\circ} \mathrm{F}\) and 150 psia. How many tubeless tires can it fill to 44.7 psia at \(70^{\circ} \mathrm{F}\) if each tire has a volume of 1.5 \(\mathrm{ft}^{3}\) and the compressed air tank is not refilled? The tank air temperature remains constant at \(70^{\circ} \mathrm{F}\) because of heat transfer through the tank's large surface area.

The universal gas constant \(R_{0}\) is equal to \(49,700 \mathrm{ft}^{2} /\left(\mathrm{s}^{2} \cdot^{\circ} \mathrm{R}\right)\) or \(8310 \mathrm{m}^{2} /\left(\mathrm{s}^{2} \cdot \mathrm{K}\right) .\) Show that these two magnitudes are equal.
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