The stagnation pressure in a Mach 2 wind tunnel operating with air is 900 kPa. A 1.0 -cm-diameter sphere positioned in the wind tunnel has a drag coefficient of \(0.95 .\) Calculate the drag force on the sphare.

Short Answer

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To solve this problem, one must calculate the cross sectional area of the sphere, compute the dynamic pressure and finally use these values in the drag force equation to obtain the desired result.

Step by step solution

01

Determination of cross-sectional area

First, calculate the cross-sectional area of the sphere: This can be obtained using the sphere's diameter \(D = 1.0\) cm. The cross-sectional area, \(A\), of a sphere is given by \(A = \pi r^2\) where \(r\) is the radius of the sphere = diameter/2 = \(1.0/2\). After converting the radius to meters (since 1cm = 0.01m), compute the area.
02

Calculation of Pressures

Use the given stagnation pressure \(P_0\) = 900 kPa (which should be converted to Pa by multiplying by 1000) and compute the dynamic pressure, which is defined to be half the stagnation pressure, that is \(P = 0.5 P_0\).
03

Calculating the drag force

Now compute the drag force, which is given by the equation \(F_D = C_D \cdot P \cdot A\) where \(C_D\) = 0.95 (drag coefficient), \(P\) is the dynamic pressure calculated in step 2, and \(A\) is the area calculated in step 1.

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