A model fan with wheel diameter 32 in. is tested at a speed of \(1750 \mathrm{rpm}\). The test fluid is air with density \(0.075 \mathrm{lbm} / \mathrm{ft}\). At its \(\mathrm{BEP}\), the fan produces \(8000 \mathrm{ft}^{3} / \mathrm{min}\) at total pressure rise of 8 in. \(\mathrm{H}_{2} \mathrm{O}\). A geometrically similar fan is to handle \(200,000 \mathrm{ft}^{3} / \mathrm{min}\) of flue gas with density \(0.050 \mathrm{lbm} / \mathrm{ft}^{3}\) and 30 in. \(\mathrm{H}_{2} \mathrm{O}\) total pressure rise. Determine the required size and speed of the flue gas fan. Note any assumptions and/or limitations.

Short Answer

Expert verified
The required size of the flue gas fan is found from the volume flow rate affinity law and it comes out to be \(D_{2}\) inches where \(D_{2}\) is solution from step 1. The required rotation speed is found from the pressure affinity law and it will be \(N_{2}\) rpm where \(N_{2}\) is solution from step 2.

Step by step solution

01

Apply the volume flow rate affinity law

The volume flow rate affinity law is \((Q_{2} / Q_{1}) = (D_{2} / D_{1})^{3}\). Substituting given data: \(200,000 / 8,000 = (D_{2} / 32)^{3}\). Solving for \(D_{2}\) will give you the diameter of the flue gas fan.
02

Apply the pressure affinity law

The pressure affinity law is \((\Delta p_{2} / \Delta p_{1}) = (D_{2} / D_{1})^{2} * (N_{2} / N_{1})^{2}\). We already know the values for \(D_{2}\) from Step 1, and \(\Delta p_{1}=8 in. H_{2}O, \Delta p_{2}=30 in. H_{2}O, D_{1}=32 in., N_{1}=1750 rpm\). The only unknown is \(N_{2}\), the speed of the second fan, which can be found by solving the equation.
03

Make assumptions and note limitations

It shall be assumed that the air and the flue gas behave as ideal gases. Any deviation from ideal behavior could affect the calculations. Moreover, it must be kept in mind that the increase in size of the fan may introduce mechanical constraints that have not been considered in the problem.

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