Chapter 2: Problem 28
On the suction side of a pump, a Bourdon pressure gage reads \(40 \mathrm{kPa}\) vacuum. What is the corresponding absolute pressure if the ocal atmospheric pressure is \(100 \mathrm{kPa}(\mathrm{abs}) ?\)
Chapter 2: Problem 28
On the suction side of a pump, a Bourdon pressure gage reads \(40 \mathrm{kPa}\) vacuum. What is the corresponding absolute pressure if the ocal atmospheric pressure is \(100 \mathrm{kPa}(\mathrm{abs}) ?\)
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Get started for freeA 30 -ft-high downspout of a house is clogged at the bottom. Find the pressure at the bottom if the downspout is filled with \(60^{\circ} \mathrm{F}\) rainwater.
A not-too-honest citizen is thinking of making bogus gold bars by first making a hollow iridium \((S=22.5)\) ingot and plating it with a thin layer of gold \((S=19.3)\) of negligible weight and volume. The bogus bar is to have a mass of 100 lbm. What must be the volumes of the bogus bar and of the air space inside the iridium so that an inspector would conclude it was real gold after weighing it in air and water to determine its density? Could lead \((S=11.35)\) or platinum \((S=21.45)\) be used instead of iridium? Would either be a good idea?
A 2 -ft-diameter hemispherical plexiglass "bubble" is to be used as a special window on the side of an above-ground swimming pool. The window is to be bolted onto the vertical wall of the pool and faces outward, covering a 2 -ft- diameter opening in the wall. The center of the opening is 4 ft below the surface. Determine the horizontal and vertical components of the force of the water on the hemisphere.
A 5 -gal, cylindrical open container with a bottom area of 120 in. \(^{2}\) is filled with glycerin and rests on the floor of an elevator. (a) Determine the fluid pressure at the bottom of the container when the elevator has an upward acceleration of \(3 \mathrm{ft} / \mathrm{s}^{2}\). (b) What resultsnt force does the container exert on the floor of the elevator during this acceleration? The weight of the container is negligible. (Note: 1 gal \(=231\) in. \(^{3}\) )
A submarine submerges by admitting seawater \((S=1.03)\) into its ballast tanks. The amount of water admitted is controlled by air pressure, because seawater will cease to flow into the tank when the internal pressure (at the hull penetration) is equal to the hydrostatic pressure at the depth of the submarine. Consider a ballast tank, which can be modeled as a vertical half- cylinder \((R=8 \mathrm{ft}\) \(L=20 \mathrm{ft}\) ) for which the air pressure control valve has failed shut. The failure occurred at the beginning of a dive from 60 ft to 1000 ft. The tank was initially filled with seawater to a depth of \(2 \mathrm{ft}\) and the air was at a temperature of \(40^{\circ} \mathrm{F}\). As the weight of water in the \(\operatorname{tank}\) is important in maintaining the boat's attitude, determine the weight of water in the tank as a function of depth during the dive. You may assume that tank internal pressure is always in equilibrium with the ocean's hydrostatic pressure and that the inlet pipe to the tank is at the bottom of the tank and penetrates the hull at the "depth" of the submarine.
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