Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 2: Problem 32

A barometric pressure of 29.4 in. Hg corresponds to what value of atmospheric pressure in psia, and in pascals?

Short Answer

Expert verified
The atmospheric pressure of 29.4 in. Hg is approximately equivalent to 14.444 psia or 99559.839 Pa.

Step by step solution

01

Convert in. Hg to psia

First, convert inches of Mercury to pressure in terms of psia. One inch of mercury (in. Hg) at 0 degrees Celsius is approximately equivalent to 0.491154 psi. Therefore, 29.4 in. Hg can be converted to psia by multiplying with the aforementioned conversion factor. In mathematical symbols, the relation is \(Pressure_{psia} = Pressure_{in.Hg} \times Conversion_{HgToPsi}\), or more precisely, \(Pressure_{psia} = 29.4 \, in.Hg \times 0.491154 \, psi/in.Hg\).
02

Compute the pressure in psia

By multiplying the original pressure by the conversion factor, you obtain the pressure in psia. So, \(Pressure_{psia} = 14.444 \, psi\). That's the pressure in pounds per square inch absolute.
03

Convert psia to Pascals

Next, convert psia to Pascals (Pa). One psi is approximately equivalent to 6894.76 Pa. Therefore, the pressure in psia can be converted to Pascals by multiplying with this conversion factor. Written mathematically, this is \(Pressure_{Pa} = Pressure_{psia} \times Conversion_{PsiToPa}\), or moreover, \(Pressure_{Pa} = 14.444 \, psi \times 6894.76 \, Pa/psi\).
04

Compute the pressure in Pascals

By multiplying the pressure in psia by the conversion factor to Pascals, you obtain the pressure in Pascals. This is \(Pressure_{Pa} = 99559.839 \, Pa\). That's the atmospheric pressure in Pascals.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 30 -ft-high downspout of a house is clogged at the bottom. Find the pressure at the bottom if the downspout is filled with \(60^{\circ} \mathrm{F}\) rainwater.

A 5 -gal, cylindrical open container with a bottom area of 120 in. \(^{2}\) is filled with glycerin and rests on the floor of an elevator. (a) Determine the fluid pressure at the bottom of the container when the elevator has an upward acceleration of \(3 \mathrm{ft} / \mathrm{s}^{2}\). (b) What resultsnt force does the container exert on the floor of the elevator during this acceleration? The weight of the container is negligible. (Note: 1 gal \(=231\) in. \(^{3}\) )

A studant needs to measure the air pressure inside a compressed air tenk but does not have ready access to a pressure gage. Using materials already in the lab, she builds a U-tube manometer using two clear 3 -ft-long plastic tubes, flexible hoses, and a tape measure. The only readily avai able liquids are water from a tap and a bottle of corn syrup. She selects the corn syrup because it has a larger density \((S G=1.4) .\) What is the maximum air pressure, in psia, that can be measured?

Find the center of pressure of an elliptical area of minor axis \(2 a\) and major axis \(2 b\) where axis \(2 a\) is vertical and axis \(2 b\) is horizontal. The center of the ellipse is a vertical distance \(h\) below the surface of the water \((h>a)\). The fluid density is constant. Will the center of pressure of the ellipse change if the fluid is replaced by another constant-density fluid? Will the center of pressure of the ellipse change if the vertical axis is tilted back an angle \(\alpha\) from the vertical about its horizontal axis? Explain.

A long, vertical wall separates seawater from fresh water. If the seawater stands at a depth of \(7 \mathrm{m},\) what depth of freshwater is required to give a zero resultant force on the wall? When the resultent force is zero, will the moment due to the fluid forces be zero? Explain.
See all solutions

Recommended explanations on Physics Textbooks

Oscillations

Read Explanation

Electric Charge Field and Potential

Read Explanation

Classical Mechanics

Read Explanation

Thermodynamics

Read Explanation

Engineering Physics

Read Explanation

Mechanics and Materials

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free