A 3 -m-diameter vertical cylindrical tank is filled with water to a depth of \(11 \mathrm{m} .\) The rest of the tank is filled with air at atmospheric pressure. What is the absolute pressure at the bottom of the tank?

Short Answer

Expert verified
The absolute pressure at the bottom of the tank is \(2.092 x 10^5 Pa\).

Step by step solution

01

Identify the Given Variables

In this problem, the following variables are outlined: Depth of water, \(h = 11m\); Density of water, \(\rho = 1000 kg/m^3\); Acceleration due to gravity, \(g = 9.81 m/s^2\); Atmospheric pressure, \(P_0 = 1.013 x 10^5 Pa\).
02

Calculate Pressure from Water

First, we calculate the pressure contributed by the water at the bottom of the tank using the formula \(P = \rho gh\). This gives us: \(P_{water} = 1000 kg/m^3 * 9.81 m/s^2 * 11 m = 1.079 x 10^5 Pa\).
03

Calculate Total Pressure at Bottom

The absolute pressure at the bottom is the sum of the atmospheric pressure and the pressure due to the water column. Thus, we get: \(P_{total} = P_{atm} + P_{water} = 1.013 x 10^5 Pa + 1.079 x 10^5 Pa = 2.092 x 10^5 Pa\).

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