Water flows through a hole in the bottom of a large, open tank with a speed of \(8 \mathrm{m} / \mathrm{s}\), Determine the depth of water in the tank. Viscous effects are negligible.

Short Answer

Expert verified
The depth of the water in the tank is approximately \(3.27 \, \mathrm{m}\).

Step by step solution

01

Identify the Given Parameters

It's given that the speed of the water flowing out of the hole is \(8 \, \mathrm{m/s}\).
02

Apply Torricelli's Theorem

Torricelli's theorem states that the speed, \(v\), of the efflux is given by \(v = \sqrt{2gh}\), where \(g\) is the acceleration due to gravity and \(h\) is the depth of the fluid above the hole.
03

Solve for Unknown

We can solve the equation from Step 2 for \(h\), the depth of the fluid, which gives us \(h = \frac{v^2}{2g}\). Substituting \(v=8 \, \mathrm{m/s}\) and \(g=9.8 \, \mathrm{m/s}^2\) into the formula gives the depth of the fluid.
04

Calculation

First calculate the value of \(v^2\), which is \(64 \, \mathrm{m}^2/\mathrm{s}^2\), and then the value of \(2g\), which is \(19.6 \, \mathrm{m/s}^2\). Dividing \(64 \, \mathrm{m}^2/\mathrm{s}^2\) by \(19.6 \, \mathrm{m/s}^2\) returns approximately \(3.27 \, \mathrm{m}\), which is the depth of the water in the tank.

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