The components of a velocity ficld are given by \(u=x+y\) \(v=x y^{3}+16,\) and \(w=0 .\) Determine the location of any stagnation points \((\mathbf{V}=0)\) in the flow field.

Short Answer

Expert verified
The stagnation points in the field are at \((2,-2)\) and \((-2,2)\)

Step by step solution

01

Setting up the equations

To obtain the stagnation points, we set the components of the velocity vector to zero. Therefore, setting u=x+y to zero gives an equation \(x+y=0\). Similarly, setting v=xy^3+16 to zero gives another equation \(xy^3+16=0\). Since w=0, it need not be taken into account as it means that there is no component of the vector in the w direction.
02

Solving for x and y

Solving the first equation \(x+y=0\) gives \(y=-x\). Substituting y in the second equation, we get \((-x)x^3+16=0\) or \(x^4=16\). Solving this we get \(x=2\) and \(x=-2\). Substituting these x values in the equation for y, we get \(y=-2\) and \(y=2\) respectively.
03

Result

The stagnation points are obtained when \(x=2, y=-2\) and \(x=-2, y=2\). Thus, these are the points on the field where the velocity vector is zero.

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