The pressure rise, \(\Delta p,\) across a pump can be expressed as \\[ \Delta p=f(D, \rho, \omega, Q) \\] where \(D\) is the impeller diameter, \(\rho\) the fluid density, \(\omega\) the rotational speed, and \(Q\) the flowrate. Determine a suitable set of dimensionless parameters.

Short Answer

Expert verified
The dimensionless parameters for the given exercise are Pi1 = (Δp) / (ρ * (ω)² * (D)²) and Pi2 = Q / (ω * (D)³).

Step by step solution

01

Define the Dimensions of the Variables

Begin by delineating the physical dimensions of each variable in the equation. Let [D] denote the dimensions of D, [Q] denote the dimensions of Q etc. Here, D (diameter) has the dimension of length (L), ρ (density) has the dimension of mass per unit volume (ML⁻³), ω (angular velocity) has the dimension of T⁻¹ (time inversed), and Q (flowrate) has the dimension of volume per unit time (L³T⁻¹). Lastly, Δp (pressure difference), has the dimension of force per unit area (ML⁻¹T⁻²) or equivalently,
02

Apply the Buckingham Pi theorem

Now apply the Buckingham Pi theorem. This theorem states that any physical law can be expressed as a relationship among dimensionless quantities. As there are five variables (i.e., Δp, D, ρ, ω, Q) and three fundamental dimensions (M, L, T), the theorem suggests there should be 5 - 3 = 2 Pi terms.
03

Define the Pi terms

Let's define the Pi terms. The choice of which variables to build the Pi terms from is arbitrary, so pick the two which appear to be the simplest, which are D (Diameter) and ρ (density). Then look for two more variables such that (with D and ρ) they form a dimensionless group. Those groups can be expressed as follows: \[Pi1 = (Delta p) / (rho * (omega)^2 * (D)^2)\] \[Pi2 = Q / (omega * (D)^3)\]

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Most popular questions from this chapter

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