A fluid flows through a horizontal 0.1-in.-diameter pipe. When the Reynolds number is \(1500,\) the head loss over a \(20-f t\) lenzth of the pipe is \(6.4 \mathrm{ft}\). Determine the fluid velocity.

Short Answer

Expert verified
The fluid velocity is \(1.04\) ft/s.

Step by step solution

01

Determine the friction factor

In this step, the friction factor for the laminar flow, \(f\), will be identified. The friction factor in laminar pipe flows \(f\) is calculated by the formula \( f = 16 / Re \), where \(Re\) is Reynolds number. Given that the Reynolds number is 1500, then friction factor \(f = 16 / 1500 = 0.01067\).
02

Apply the formula for head loss

The formula for head loss, \(h_f\), is \( h_f = f * L/D * v^2 / 2g\). Here, \(L\) is the length of the pipe is \(L = 20 * 12 = 240\) inches. \(D\) is the diameter of the pipe is \(0.1\) inches. \(h_f\) is given as \(6.4\) feet or \(6.4 * 12 = 76.8\) inches. \(g\) is gravity constant \(= 386.1\) in/s^2. Substituting into the formula, we have \( 76.8 = 0.01067 * 240/0.1 * v^2 / 2*386.1 \) or simplified \( v^2 = 76.8 * 2 * 386.1 / 0.01067 * 240/0.1 \).
03

Calculate the velocity

Solving the equation from step 2, we get \( v = \sqrt{76.8 * 2 * 386.1 / (0.01067 * 240/0.1) } \). Solving for \(v\), we get \(v = 12.5\) in/s, or converting units, we have \(v = 1.04\) ft/s.

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Most popular questions from this chapter

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