Ruby lasers are at a wavelength of 694 nm. A certain ruby crystal has Cr ions (which are the atoms that lase). The lasing transition is between the first excited state and the ground state, and the output is a light pulse lasting 2.00μs. As the pulse begins, 60.0% of the Cr ions are in the first excited state and the rest are in the ground state. What is the average power emitted during the pulse? (Hint:Don’t just ignore the ground-state ions.)

Short Answer

Expert verified

The average power emitted during the pulse is 1.1×106W.

Step by step solution

01

The given data

The wavelength of the ruby lasers,λ=694nm

The output pulse last,t=2μs

As the pulse begins, 60% are in a first excited state and 40% in the ground state.

Consider the known data as below.

Plank’s constant,h=6.63×10-34Js

Speed of light,c=3×108ms

02

Understanding the concept of average power and Plank’s relation:

The rate of energy flow in every pulse is called average power.

Photon energy is the energy carried by a single photon. The amount of energy is directly proportional to the magnetic frequency of the photon and thus, equally, equates to the wavelength of the wave. When the frequency of photons is high, its potential is high.

Using the equation of Plank's relation, to get the energy of the photon that is being emitted by the laser. Now, using this value in the power equation considering the criteria of emitted photons, to find the average power of the emitted pulse.

Formulas:

The energy of the photon due to Planck’s relation,

E=hcλ ….. (1)

The average power of the emitted pulse is,

Pavg=(N1-N2)EphotonΔt ….. (2)

03

Calculation of the average power:

At first, the energy of the photon is calculated using the given data in equation (1) as follows:

E=6.63×10-34J.s3×108m/s694×10-9m=2.87×10-19J

Now, according to the problem consider the known data due to the absorption of the emitted photons of the Cr ions in the excited state by the ions in the ground state.as below.

The number of atoms in the excited state,N1=0.6 and

The number of atoms in the ground state, N2=0.4

Thus, the average power emitted during the pulse is given using equation (2) and, the given data is as follows.

Pavg=0.6-0.42.87×1019J0.2×10-6s=1.1×106J/s=1.1×106W

Hence, the value of the average power is 1.1×106W.

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Most popular questions from this chapter

The beam from an argon laser (of wavelength 515 nm) has a diameter 3.00 mm of and a continuous energy output rate of 5.00 W. The beam is focused onto a diffuse surface by a lens whose focal length f is 3.50 cm . A diffraction pattern such as that of Fig. 36-10 is formed, the radius of the central disk being given by R=1.22d(see Eq. 36-12 and Fig. 36-14). The central disk can be shown to contain 84% of the incident power. (a) What is the radius of the central disk? (b) What is the average intensity (power per unit area) in the incident beam? (c) What is the average intensity in the central disk?

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