Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 9: Q110P (page 255)

A 140 g ball with speed 7.8ms strikes a wall perpendicularly and rebounds in the opposite direction with the same speed. The collision lasts 3.80 ms .What are the magnitudes of the (a) impulse and (b) average force on the wall from the ball during the elastic collision?

Short Answer

Expert verified
  1. Magnitude of impulse,Jis2.18kg.ms.
  2. Magnitude of the average force on the wall from the ball, F is 575 N .

Step by step solution

01

Understanding the given information

  1. Mass of the ball, m = 140 g.
  2. Speed of the ball,vi=7.8ms.
  3. Time of collision, t = 3.80 ms .
02

Concept and formula used in the given question

Use the concept of impulse. Using the equation of impulse and find the impulse and then using the same equation of time involved, then find the average force. The equations are given below.

J=m∆VFt=m∆V

03

(a) Calculate the magnitude of impulse

Magnitude of impulse:

Ball rebounds back with same velocity, we can write,

J=0.14(-v-(v)=0.14×2v=0.14×2×7.8=-2.18kg.ms

Magnitude of impulse is J=2.18kg.ms

04

(b) Calculate the magnitude of impulse average force on the wall from the ball during the elastic collision

Magnitude of the average force on the wall from the ball.

Consider the formulas J=m∆VandFt=m∆V.

Use value of J here and solve as:

F(3.80×10-3)=m∆VF=2.183.80×10-3F=574.7NF≈575N

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An unmanned space probe (of mass mand speed vrelative to the Sun) approaches the planet Jupiter (of mass Mand speed VJrelative to the Sun) as shown in Fig. 9-84. The spacecraft rounds the planet and departs in the opposite direction. What is its speed (in kilometers per second), relative to the Sun, after this slingshot encounter, which can be analyzed as a collision? Assume v=10.5kmsand VJ=13.0kms(the orbital speed of Jupiter).The mass of Jupiter is very much greater than the mass of the spacecraft (M ≫m).

Two blocks of masses1.0 kgand3.0 kgare connected by a spring and rest on a frictionless surface. They are given velocities toward each other such that the 1.0 kgblock travels initially at 1.7 m/stoward the center of mass, which remains at rest. What is the initial speed of the other block?

Two average forces. A steady stream of 0.250 kgsnowballs is shot perpendicularly into a wall at a speed of 4.00 m/s . Each ball sticks to the wall. Figure 9-49 gives the magnitude F of the force on the wall as a function of time t for two of the snowball impacts. Impacts occur with a repetition time interval ∆tr=50.0ms, last a duration time interval ∆td=10ms, and produce isosceles triangles on the graph, with each impact reaching a force maximum Fmax=20N.During each impact, what are the magnitudes of (a) the impulse and (b) the average force on the wall? (c) During a time interval of many impacts, what is the magnitude of the average force on the wall?

A75 kgman rides on a39 kgcart moving at a velocity of 2.3 m/s. He jumps off with zero horizontal velocity relative to the ground. What is the resulting change in the cart’s velocity, including sign?

In the overhead view of Figure, a 300 g ball with a speed v of 6.0 m/sstrikes a wall at an angle θof30°and then rebounds with the same speed and angle. It is in contact with the wall for10 ms. In unit vector notation, What are (a) the impulse on the ball from the wall and (b) The average force on the wall from the ball?
See all solutions

Recommended explanations on Physics Textbooks

Physics of Motion

Read Explanation

Translational Dynamics

Read Explanation

Engineering Physics

Read Explanation

Kinematics Physics

Read Explanation

Electricity and Magnetism

Read Explanation

Conservation of Energy and Momentum

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free