A 140 g ball with speed 7.8ms strikes a wall perpendicularly and rebounds in the opposite direction with the same speed. The collision lasts 3.80 ms .What are the magnitudes of the (a) impulse and (b) average force on the wall from the ball during the elastic collision?

Short Answer

Expert verified
  1. Magnitude of impulse,Jis2.18kg.ms.
  2. Magnitude of the average force on the wall from the ball, F is 575 N .

Step by step solution

01

Understanding the given information

  1. Mass of the ball, m = 140 g.
  2. Speed of the ball,vi=7.8ms.
  3. Time of collision, t = 3.80 ms .
02

Concept and formula used in the given question

Use the concept of impulse. Using the equation of impulse and find the impulse and then using the same equation of time involved, then find the average force. The equations are given below.

J=mVFt=mV

03

(a) Calculate the magnitude of impulse

Magnitude of impulse:

Ball rebounds back with same velocity, we can write,

J=0.14(-v-(v)=0.14×2v=0.14×2×7.8=-2.18kg.ms

Magnitude of impulse is J=2.18kg.ms

04

(b) Calculate the magnitude of impulse average force on the wall from the ball during the elastic collision

Magnitude of the average force on the wall from the ball.

Consider the formulas J=mVandFt=mV.

Use value of J here and solve as:

F(3.80×10-3)=mVF=2.183.80×10-3F=574.7NF575N

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Fig. 9-77, two identical containers of sugar are connected by a cord that passes over a frictionless pulley. The cord and pulley have negligible mass, each container and its sugar together have a mass of 500 g, the centers of the containers are separated by 50 mm, and the containers are held fixed at the same height. What is the horizontal distance between the center of container 1 and the center of mass of the two-container system (a) initially and (b) after 20 g of sugar is transferred from container 1 to container 2? After the transfer and after the containers are released, (c) in what direction and (d) at what acceleration magnitude does the center of mass move?

A man (weighing915N) stands on a long railroad flatcar (weighing2415N) as it rolls at 18.2msin the positive direction of an xaxis, with negligible friction, then the man runs along the flatcar in the negative xdirection at4.00msrelative to the flatcar. What is the resulting increase in the speed of the flatcar?

During a lunar mission, it is necessary to increase the speed of a spacecraft by 2.2mswhen it is moving at400msrelative to the Moon. The speed of the exhaust products from the rocket engine is1000msrelative to the spacecraft. What fraction of the initial mass of the spacecraft must be burned and ejected to accomplish the speed increase?

A space vehicle is travelling at 4300 km/hrelative to Earth when the exhausted rocket motor (mass 4m)is disengaged and sent backward with a speed of 82 km/hrelative to the command module ( mass m).What is the speed of the command module relative to Earth just after the separation?

Figure 9-53 shows an approximate plot of force magnitude F versus time t during the collision of a 58 gSuperball with a wall. The initial velocity of the ball is 34 m/sperpendicular to the wall; the ball rebounds directly back with approximately the same speed, also perpendicular to the wall. What isFmaxthe maximum magnitude of the force on the ball from the wall during the collision?

Fig. 9-53

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free