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Chapter 9: Q111P (page 255)

A rocket sled with a mass of 2900 kg moves at 250mson a set of rails. At a certain point, a scoop on the sled dips into a trough of water located between the tracks and scoops water into an empty tank on the sled. By applying the principle of conservation of linear momentum, determine the speed of the sled after 920 kgof water has been scooped up. Ignore any retarding force on the scoop.

Short Answer

Expert verified

Speed of sled after 920 kg water is scooped up is 190ms.

Step by step solution

01

Step 1: Given

  1. Rocket sled mass is,m1=2900kg.
  2. Speed of sled is,v1=250ms.
  3. Mass of water is, m2=920kg.
02

Determine the formulas and solve as:

Formula is as follow:

m1v1=(m1+m2)v2

Here, m1, m2 are masses, v1, v2 are velocities.

03

Determining the speed of sled after 920 kg water is scooped up

According to the law of conservation of momentum,

m1v1=(m1+m2)v22900×250=(2900×920)×v2v2=189.79ms

In two significant figure:

v2=190ms

This is the speed of the water which is equal to the speed of the sled.

Therefore, speed of the sled after 920 kg water is scooped up is190ms

Using the law of conservation of momentum, the speed of one of the objects undergoing elastic collision can be found if the speed of the system after collision is known.

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