Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 9: Q111P (page 255)

A rocket sled with a mass of 2900 kg moves at 250mson a set of rails. At a certain point, a scoop on the sled dips into a trough of water located between the tracks and scoops water into an empty tank on the sled. By applying the principle of conservation of linear momentum, determine the speed of the sled after 920 kgof water has been scooped up. Ignore any retarding force on the scoop.

Short Answer

Expert verified

Speed of sled after 920 kg water is scooped up is 190ms.

Step by step solution

01

Step 1: Given

  1. Rocket sled mass is,m1=2900kg.
  2. Speed of sled is,v1=250ms.
  3. Mass of water is, m2=920kg.
02

Determine the formulas and solve as:

Formula is as follow:

m1v1=(m1+m2)v2

Here, m1, m2 are masses, v1, v2 are velocities.

03

Determining the speed of sled after 920 kg water is scooped up

According to the law of conservation of momentum,

m1v1=(m1+m2)v22900×250=(2900×920)×v2v2=189.79ms

In two significant figure:

v2=190ms

This is the speed of the water which is equal to the speed of the sled.

Therefore, speed of the sled after 920 kg water is scooped up is190ms

Using the law of conservation of momentum, the speed of one of the objects undergoing elastic collision can be found if the speed of the system after collision is known.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Figure 9-28 shows four groups of three or four identical particles that move parallel to either the x-axis or the y-axis, at identical speeds. Rank the groups according to center-of-mass speed, greatest first.

In Fig. 9-77, two identical containers of sugar are connected by a cord that passes over a frictionless pulley. The cord and pulley have negligible mass, each container and its sugar together have a mass of 500 g, the centers of the containers are separated by 50 mm, and the containers are held fixed at the same height. What is the horizontal distance between the center of container 1 and the center of mass of the two-container system (a) initially and (b) after 20 g of sugar is transferred from container 1 to container 2? After the transfer and after the containers are released, (c) in what direction and (d) at what acceleration magnitude does the center of mass move?

An electron undergoes a one-dimensional elastic collision with an initially stationary hydrogen atom. What percentage of the electron’s initial kinetic energy is transferred to kinetic energy of the hydrogen atom? (The mass of the hydrogen atom is 1840 times the mass of the electron)

Figure 9-73 shows an overhead view of two particles sliding at constant velocity over a frictionless surface. The particles have the same mass and the same initial speed V = 4.00 m/s, and they collide where their paths intersect. An xaxis is arranged to bisect the angle between their incoming paths, such thatθ=40.0°. The region to the right of the collision is divided into four lettered sections by the xaxis and four numbered dashed lines. In what region or along what line do the particles travel if the collision is (a) completely inelastic, (b) elastic, and (c) inelastic? What are their final speeds if the collision is (d) completely inelastic and (e) elastic?

A big olive (m=0.50kg) lies at the origin of an XYcoordinates system, and a big Brazil nut ( M=1.5kg) lies at the point (1.0,2.0)m . At t=0 , a force F0=(2.0i^-3.0j)^ begins to act on the olive, and a force localid="1657267122657" Fn=(2.0i^-3.0j)^begins to act on the nut. In unit-vector notation, what is the displacement of the center of mass of the olive–nut system att=4.0s with respect to its position att=0?
See all solutions

Recommended explanations on Physics Textbooks

Physics of Motion

Read Explanation

Dynamics

Read Explanation

Translational Dynamics

Read Explanation

Fluids

Read Explanation

Famous Physicists

Read Explanation

Astrophysics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free