When resistors 1 and 2 are connected in series, the equivalent resistance is 16.0 Ω. When they are connected in parallel, the equivalent resistance is 3.0 Ω. What are the smaller resistance and the larger resistance of these two resistors?

Short Answer

Expert verified

The smaller resistance is R1=4Ωand the larger resistance isR2=12Ω

Step by step solution

01

Given

  1. The equivalent resistance of the series arrangement isReq=16Ω
  2. The equivalent resistance of the parallel arrangement is Req=3Ω
02

Determining the concept

Use the concept of equivalent resistance for series circuit and parallel circuit. Using the equations, find the larger and the smaller resistance.

Formulae are as follow:

Resistance in series,

Req=R1+R2

Resistance in parallel,

1Req=1R1+1R2

03

Determining the smaller and larger resistance.

The two equations can be written as ,

Req=R1+R216=R1+R2.......................11Req=1R1+1R2

Write it as,

R=R1R2R1+R23.0Ω=R1R2R1+R2.............................2

Using the value of R1+R2from equation (1) in equation (2),

3.0=R1R216RR=3.0×16=48

From the equation (1), it can be determined that R1=4Ωand R2=12Ω

These values also satisfy the equation (2). So, the smaller resistance is R1=4Ωand the larger resistance isR2=12Ω

Hence, the smaller resistance is R1=4Ωand the larger resistance isR2=12Ω

Therefore, by using the concept of equivalent resistance for series circuit and parallel circuit smaller and larger resistance can be determined.

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