How many electrons would have to be removed from a coin to leave it with a charge of +1.0×107C ?

Short Answer

Expert verified

The number of electrons to be removed is6.3×1011.

Step by step solution

01

The given data 

Charge of the coin, q=+1.00×107C

02

Understanding the concept of quantization of charge 

As we know that a charged particle emits energy in the form of packets, thus, the number of electrons emitted or present can be considered as multiple factors of the electronic charge.

Formula:

The number of electrons present, n=q/e (1)

03

Calculation of the number of electrons

Using the equation (1) and the given data, we can get the number of electrons removed from the coin as given:

n=1.00×107C1.60×1019C=6.3×1011

Hence, the number of electrons removed is 6.3×1011

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