Chapter 21: Q53P (page 628)

Question: What would be the magnitude of the electrostatic force between two 1.00Cpoint charges separated by a distance of (a) 1 .00 mand (b) 1.00 kmif such point charges existed (they do not) and this configuration could be set up?

Expert verified

Answer:

The magnitude of the electrostatic force for distance of 1.00 m is $9.00 \times 10^{9} N$ .
The magnitude of the electrostatic force for distance of 1.00 km is $9.00 \times 10^{3} N$ .

Step by step solution

Two point charges of charge are separated by the distance.

Using the concept of Coulomb's law, we can find the magnitude of the required force between the particles.

Formula:

Magnitude of electrostatic force between any two particles, $F = k \frac{|q_{1}| |q_{2}|}{r^{2}}$ . (i)

Using the given data in equation (i), we get the magnitude of the force as follows:

$F = \frac{(9 \times 10^{9} N m^{2} / C^{2}) {(1.00 C)}^{2}}{{(1.00 m)}^{2}} = 9.00 \times 10^{9} N$

Hence, the value of the force is $9.00 \times 10^{9} N$

Using the given data in equation (i), we get the magnitude of the force as follows:

$F = \frac{(9 \times 10^{9} N m^{2} / C^{2}) {(1.00 C)}^{2}}{{(1.00 \times 10^{3} m)}^{2}} = 9.00 \times 10^{3} N$

Hence, the value of the force is $9.00 \times 10^{3} N$

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