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Chapter 21: Q66P (page 629)

An electron is in a vacuum near Earth’s surface and located aty=0on a vertical yaxis. At what value of yshould a second electronbe placed such that its electrostatic force on the first electron balancesthe gravitational force on the first electron?

Short Answer

Expert verified

y=−5.1m

Step by step solution

01

Given

Electron is in a vacuum near Earth’s surface and located at y = 0

02

Understanding the concept

Use Coulomb’s law to solve the problem.

03

Calculate the value of y

with,F=meg

y2=ke2meg=(9.00×109Nm2/C2)(1.60×10−19C)2(9.11×10−31kg)(9.8m/s2)

Which leads toy=±5.1m . We choose y=−5.1msince the second electron must be below the first one, so that the repulsive force (acting on the first) is in the direction opposite to the pull of Earth’s gravity.

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Most popular questions from this chapter

Of the chargeQinitially on a tiny sphere, a portion qis to be transferred to a second, nearby sphere. Both spheres can be treated as particles and are fixed with a certain separation. For what value of q/Qwill the electrostatic force between the two spheres be maximized?

A particle of charge Qis fixed at the origin of an x-ycoordinate system. Att=0a particle (m=0.800g, q=4.00μC) is located on the xaxis atx=20.0cm, moving with a speed of50.0m/sin the positive ydirection. For what value of Qwill the moving particle execute circular motion? (Neglect the gravitational force onthe particle.)

Figure 21-11 shows four situations in which five charged particles are evenly spaced along an axis. The charge values are indicated except for the central particle, which has the same charge in all four situations. Rank the situations according to the magnitude of the net electrostatic force on the central particle, greatest first.

In Fig. 21-25, four particles form a square. The charges areq1=q2=Q, and q2=q3=q. (a) What is Q/qif the net electrostatic force on particles 1 and 4 is zero? (b) Is there any value of qthat makes the net electrostatic force on each of the four particles zero? Explain.

In Fig. 21-44, what are the (a) magnitude and (b) direction of the net electrostatic force on particle 4 due to the other three particles? All four particles are fixed in the xy−plane, and,q1=−3.20×10−19 C,,q2=+3.20×10−19 C,q3=+6.40×10−19 C,q4=+3.20×10−19 C,θ1=35.00,d1=3.00 cmand d2=d3=2.00 cm.
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