A 18 .0 Wdevice has 9.00 Vacross it. How much charge goes through the device in 4.00 h?

The given data can be listed below as:

• Power of the device is, P = 18.0 W .
• Potential difference is, V = 9.00 V .
• Time interval is,$t=4hr=1.44\times {10}^{4}s$

First, we need to find the current flowing through the device. Then finding the product of the current and time, we can estimate the amount of charge, Q.

Formulae:

The electric power generated in the circuit is,

P = i x V … (i)

The electric current in the circuit is,

$i=\frac{P}{V}$ … (ii)

The current flowing through the area is,

$i=\frac{Q}{t}$ … (iii)

The charge flowing through the area is,

$Q=it$ … (iv)

Substituting the given values in equation (ii), we can get the value of the current flowing as follows:

$$\begin{gathered} i=\frac{18.0W}{9.00V} \\ =2.00A \end{gathered}$$

The amount of charge going through the device can be calculated using the current value in equation (iv) as follows:

$$\begin{gathered} Q=2.00A\times 1.44\times {10}^{4}s \\ =2.88\times {10}^{4}C \end{gathered}$$

Hence, the value of the charge entering into the device is$2.88\times {10}^{4}C$ .