Light of wavelength 500nm diffracts through a slit of width2μm and onto a screen that is 2maway. On the screen, what is the distance between the center of the diffraction pattern and the third diffraction minimum?

Short Answer

Expert verified

The distance between the center of the diffraction pattern and the third diffraction minimum is1.5mm .

Step by step solution

01

Given data:

The wavelength of incident light λ=500nm:

Slit width: d=2mm

Distance of screen from slit: D=2m

02

Diffraction from a single slit:

The distance of the mth order single slit diffraction minima from thecentral maxima for slit width d and screen distance D is

x=mλDd .....(1)

Here,λ is the wavelength of the incident light.

03

Determining the distance of the third minimal from central maxima

Calculate the distance of the third minima from the central maxima by substituting known values into equation (1).

x=3×500×10-9m×2m2×10-3m=0.0015m=1.5mm

Thus, the required distance is 1.5mm.

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