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Chapter 36: Q3Q (page 1107)

For three experiments, Fig.36-31 gives the parameter of Eq. 36-20 versus angle in two-slit interference using light of wavelength 500 nm. The slit separations in the three experiments differ. Rank the experiments according to (a) the slit separations and (b) the total number of two slit interference maxima in the pattern, greatest first.

Short Answer

Expert verified
  1. The rank will be A, B and C
  2. The rank will be C, B and A.

Step by step solution

01

The given data

Given for three experiments, the parameterβ of versus angleθ in two-slit interference using light of wavelength 500 nm.

The slit separations in the three experiments differ.

02

Concept and Formula used

In a double split experiment for diffraction,

β=πdλsinθ

dis slit separation , andλ is wavelength.

03

(a) Rank according to slit separation

Now, from the equation

β=πdλsinθ

It is clear that graph will be greater for larger values of d.

So Rank according to slit width (greatest first) is A, B and C.

04

(b) Rank according to total diffraction maxima

Since the wavelengths are same, the smaller slit will produce more maxima.

So, the rank will be C, B and A.

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Most popular questions from this chapter

A spy satellite orbiting at 160 km above Earth’s surface has a lens with a focal length of 3.6 m and can resolve objects on the ground as small as 30 cm. For example, it can easily measure the size of an aircraft’s air intake port. What is the effective diameter of the lens as determined by diffraction consideration alone? Assume λ=550nm.

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