A diffraction grating with a width of 2.0 cm contains 1000 lines/cm across that width. For an incident wavelength of 600 nm, what is the smallest wavelength difference this grating can resolve in the second order?

Short Answer

Expert verified

The wavelength difference can resolve in the second order is Δλ=0.15nm.

Step by step solution

01

The resolving power

It is known the resolving power of a grating is given byR=Nm=λavgλ, where Nis the number of rulings in the grating and mis the order of the linesλavg, is the average of wavelengths and λis the separation.

02

The wavelength difference

Here, the width of 2.0 cm contains1000lines/cm . So, there are totalN=2×1000=2000lines .

Given that the grating is in the second order, som=2 andλavg=600nm . So, the wavelength difference can be obtained as:

Δλ=λavgNm=600nm2000×2=0.15nm

Thus, the smallest wavelength difference that this grating can resolve in the second order is Δλ=0.15nm.

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