If first-order reflection occurs in a crystal at Bragg angle3.4°, at what Bragg angle does second-order reflection occur from the same family of reflecting planes?

Short Answer

Expert verified

The angle will be 6.8 degrees.

Step by step solution

01

Introduction of diffraction

Diffraction is a phenomena in which the interference or the bending of waves occurs around the corners of the opening or obstacle through or on which it strikes.

The diffraction formula is following,

=2dsinθλ=wavelengthd=spacingθ=bragg anglen=order of diffraction

02

Step 2: Identification of the given data

The bragg angle is, θ1=3.4°.

03

Determination of the Bragg angle at which second order reflection

From the given relationship of the wavelengths the angle will be,

2dsinθ22dsinθ1=2λ1λsinθ2=2sinθ1

Substitute all the value in the above equation.

sinθ2=2×sin3.4°sinθ2=0.1186θ2=sin-10.1186θ2=6.80

Hence the angle is,6.80.

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