In Fig. 36-47, first-order reflection from the reflection planes shown occurs when an x-ray beam of wavelength0.260nmmakes an angleθ=63.8° with the top face of the crystal. What is the unit cell sizea0?

Short Answer

Expert verified

The unit cell distance is 0.570nm.

Step by step solution

01

Bragg’s law

Diffraction is a phenomena in which the interference or the bending of waves occurs around the corners of the opening or obstacle through or on which it strikes.

The diffraction formula is following,

=2dsinθλ=wavelengthd=spacingθ=bragg anglen=order of diffraction

02

Step 2: Identification of the given data

The wavelength is,λ=0.260nm.

The angle is, 63.8°.

The angle of incidence on the reflection planes is, θ=63.8°-45=18.80.

The order of diffraction is,n=1 .

03

 Step 3: The unit cell size

From the given figure it is clear that the relation following will be formed,

d=a02a0=2d

Now from the bragg’s law,

2d=2nλ2sinθ

Substitute all the value in the above equation.

a0=1×0.260nm2×sin18.8°a0=0.570nm

So the unit cell distance is0.570nm .

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Most popular questions from this chapter

The distance between the first and fifth minima of a single slit diffraction pattern is 0.35mmwith the screen 40cmaway from the slit, when light of wavelength role="math" localid="1663070418419" 550nmis used. (a) Find the slit width. (b) Calculate the angle role="math" localid="1663070538179" θ of the first diffraction minimum.

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