Light of wavelength 633nmis incident on a narrow slit. The angle between the first diffraction minimum on one side of the central maximum and the first minimum on the other side is 1.20°. What is the width of the slit?

Short Answer

Expert verified

The width of slit is 3.023×10-5m.

Step by step solution

01

Identification of given data

The wavelength of the light is λ=633nm.

The angle of diffraction between central minima and second order minima is θ=1.20°.

The order of first minima is m=1.

02

Concept used

The diffraction is the phenomenon in which the light bends on the edges of the slit and pattern of light is formed on a screen.

03

Determination of width of slit

The width of slit is given as:

mλ=dsinθ

Substitute all the values in equation.

1633nm10-9m1nm=dsin0.429°d=3.023×10-5m

Therefore, the width of slit is 3.023×10-5m.

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