An electric dipole consists of charges +2eand -2eseparated by 0.78 nm. It is in an electric field of strength$3.4\times {10}^{6}N/C$. Calculate the magnitude of the torque on the dipole when the dipole moment is (a) parallel to, (b) perpendicular to, and (c) antiparallel to the electric field.

• a)Charges of values, +2e and-2e.
• b) Separation between the charges, r =0.78 nm.
• c) Magnitude of the electric field,$E=3.4\times {10}^{6}N/C$

Using the concept of the torque acting on a dipole, the torque for the given cases is given by considering the given situations of the angle made by the dipole to the electric field.

Formula:

The magnitude of torque $\left(\zeta \right)$in terms of the magnitudes of the electric field E and the dipole moment p = qd is given by:

$\zeta =pE\sin \theta$

From equation (i), we can see that the torque for$\theta =0°$ is given as:

$$\begin{gathered} \zeta =pE\sin 0° \\ =0. \end{gathered}$$

Hence, the value of the torque is 0.

From equation (i), we can see that the torque for$\theta =90°$is given as:

$$\begin{gathered} \zeta =pE \\ =\left(2.16\times {10}^{-19}C\right)\left(0.78\times {10}^{-9}m\right)\left(3.4\times {10}^{6}N/C\right) \\ =8.5\times {10}^{-22}N.m \end{gathered}$$

Hence, the value of the torque is$8.5\times {10}^{-22}N.m$.

From equation (i), we can see that the torque for$\theta =180°$ is given as:

$$\begin{gathered} \zeta =pE\sin 180° \\ =0. \end{gathered}$$

Hence, the value of the torque is 0.