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Chapter 22: Q5P (page 653)

A charged particle produces an electric field with a magnitude of2.0N/Cat a point that is50cmaway from the particle. What is the magnitude of the particle’s charge?

Short Answer

Expert verified

The magnitude of the particle’s charge is5.6×10-11C

Step by step solution

01

The given data

a) The magnitude of the electric field,E=2.0N/C

b) The distance of the point from the particle,R=50 cmor0.5m

02

Understanding the concept of electric field 

Using the concept of the electric field at a given point, we can get its charge value from the given formula.

Formula:

The magnitude of the electric field,E=q4πεoR2 (1)

where R = The distance of field point from the charge, and q = charge of the particle

03

Calculation of the charge of the particle

Using the formula of the electric field of equation (i) and the given data, we can get the charge of the particle as follows:

q=4πε0R2E=2.00N/C0.50m28.99×109N.m2C2=5.6×10-11 C

Hence, the value of the charge is 5.6×10-11 C

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