A charge of1.50×10-8Clies on an isolated metal sphere of radius 16.0 cm. With V=0at infinity, what is the electric potential at points on the sphere’s surface?

Short Answer

Expert verified

The electric potential at points on the sphere’s surface is V=844V.

Step by step solution

01

Given data:

For the isolated metal sphere:

The radius, R=16.0cm

The value of the charge q=1.50×10-8C

At infinity, V=0

02

Determining the concept:

Use the equation of the electric potential at points on the sphere’s surface.

The electric potential is defined as the amount of work energy needed to move a unit of electric charge from a reference point to the specific point in an electric field.

Formula:

The electric potential is define by,

V=14πε0qR=kqR

Here, V is electric potential, R is distance between the point charges, q is charge, ε0is the permittivity of free space, and k is the Coulomb’s constant having a value 9×109N.m2/C2.

03

Determining the electric potential on the sphere’s surface:

The electric potential on the sphere is,

V=14πε0qR=kqR

Substitute known values in the above equation.

V=9.0×109×1.5×10-80.16=843.7volts844volts

Hence, the electric potential at points on the sphere’s surface is 844 V.

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