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Chapter 24: Q18P (page 711)

Two charged particles are shown in Fig. 24-39a. Particle 1, with charge q1, is fixed in place at distance d. Particle 2, with charge q2, can be moved along the xaxis. Figure 24-39bgives the net electric potential Vat the origin due to the two particles as a function of the xcoordinate of particle 2. The scale of the xaxis is set by xs = 16.0 cm. The plot has an asymptote of V = 5.76 x 10-7 Vas x→∞What is q2in terms of e?

Short Answer

Expert verified

The charge on q2 is -32e.

Step by step solution

01

Given

Charge q1 is fixed in a place at a distance d.

charge q2 can move along x-axis.

02

Understanding the concept

When the charge q2 is infinitely far away, the potential at the origin is due only to q1. This means the asymptote represents the potential due to the charge q1 .

V1=q14πε0d

03

Calculate q2 in terms of e

The asymptote represents the potential due to the charge q1. Therefore-

5.76×10-7V=q14πε0dq1d=6.41×10-17C/m

If the charge q2 is located at x = 0.08 m, the net potential vanishes

V1+V2=0kq20.08m+kq1d=0q2=-q1d0.08m=-5.13×10-18C=-5.13×10-18C1.6×10-19C/1e=-32e

Interms of e the charge on q2 is -32e.

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