(a) If an isolated conducting sphere10cmin radius has a net charge of4.0μCand ifV=0at infinity, what is the potential on the surface of the sphere? (b) Can this situation actually occur, given that the air around the sphere undergoes electrical breakdown when the field exceeds3.0MV/m?

Short Answer

Expert verified

a) The potential on the surface of the sphere is, 3.6×105V.

b) The situation is not possible

Step by step solution

01

Step 1: Identification of the given data

For the isolated conducting sphere

Its radius r=10cmand its charge q=4.0μC, V=0at infinity.

02

Understanding the concept

Electric Potential is given by,V=14πεo·qr

03

(a) Calculate the potential on the surface of the sphere

The electric potential is expressed as,

V=14πεo·qr

Substitute all the value in the above equation.

V=9.0×109N.m2/C2×4.0×10-6C0.10mV=3.6×105V

Hence the potential on the surface of the sphere is, 3.6×105V.

04

(b) Find out if this situation canactually occur, given that the air around the sphere undergoes electrical breakdown when the field exceeds 3.0MV/m

The field just outside the sphere is expressed as,

E=14πεo·qr2E=Vr

Substitute all the value in the above equation.

E=3.6×105V0.10m=3.6×106V/m

Hence the value is exceeds3.0MV/m, so this situation cannot occur.

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