Using the loop rule, derive the differential equation for an LCcircuit (EquationLd2qdt2+1Cq=0).

Short Answer

Expert verified

The differential equation for a circuit is d2qdt2+qLC=0.

Step by step solution

01

The given data

An LC circuit is given.

02

Understanding the concept of Kirchhoff’s loop rule

Kirchhoff's loop rule states that the sum of all the electric potential differences around a loop is zero. It is also sometimes called Kirchhoff's voltage law or Kirchhoff's second law. By using the loop rule, we can find the differential equation for an LC circuit from equation 30-35, when the emf voltage is given. Further, from the relation between charge and capacitance, by equating this equation, we can find the differential equation.

Formulae:

The voltage equation due to the current rate through an inductor, ε=-Ldidt(i)

The charge across a capacitor, q=CV(ii)

03

Calculation of the differential equation of the LC circuit

Using the loop rule, we can get the voltage equation as follows:

V-ε=0

Now, substituting equations (i) and (ii), we can get that

qc+Ldidt=01

But, the rate of current can be given as:

didt=ddtdqdt=d2qdt2

Now, substituting the above value in equation (1), we can get the required differential equation for the LC circuit as follows:

qC+Ld2qdt2=0d2qdt2+qLC=0

Hence, the differential equation of a LC circuit is d2qdt2+qLC=0.

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Most popular questions from this chapter

An ac generator with emfε=εmsinωdt, whereεm=25.0Vandωd=377rad/s, is connected to a4.15μFcapacitor. (a) What is the maximum value of the current? (b) When the current is a maximum, what is the emf of the generator? (c) When the emf of the generator isεm=-12.5Vand increasing in magnitude, what is the current?

A 1.50μFcapacitor is connected, as in the Figure to an ac generator with m=30.0V. (a) What is the amplitude of the resulting alternating current if the frequency of the emf is1.00kHz? (b) What is the amplitude of the resulting alternating current if the frequency of the emf is 8.00kHz?

In an oscillating LCcircuit L=1.10mH, andC=4.00μF. The maximum charge on the capacitor is3.00μC. Find the maximum current.

An air conditioner connected to a 120 V RMS ac line is equivalent to a12.0Ω resistance and a 1.30Ωinductive reactance in series. (a) Calculate the impedance of the air conditioner. (b) Calculate the average rate at which energy is supplied to the appliance.

A single loop consists of inductors (L1,L2,......), capacitors (C1,C2,......), and resistors (R1,R2,......) connected in series as shown, for example, in Figure-a. Show that regardless of the sequence of these circuit elements in the loop, the behavior of this circuit is identical to that of the simple LCcircuit shown in Figure-b. (Hint:Consider the loop rule and see problem) Problem:- Inductors in series.Two inductors L1 and L2 are connected in series and are separated by a large distance so that the magnetic field of one cannot affect the other.(a)Show that regardless of the sequence of these circuit elements in the loop, the behavior of this circuit is identical to that of the simple LC circuit shown in above figure (b). (Hint: Consider the loop rule)

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