A 1.50mHinductor in an oscillatingLCcircuit stores a maxi- mum energy of 10.0μJ. What is the maximum current?

Short Answer

Expert verified

The maximum current is0.115A.

Step by step solution

01

Step 1: Given

Umax=100μJ=10×10-6J

L=1.5mH=1.5×10-3H

02

Determining the concept

By using the formula for maximum energy in the LCcircuit and substituting the given values, find the maximum current.

Formulae are as follows:

Umax=12LI2

Where,

U = magnetic energy.

L = inductance of solenoid.

I = current.

03

Determining the maximum current

Umax=12LI2

Rearranging the terms,

I2=2UmaxLI=2UmaxLI=2×10×10-61.5×10-3I=0.005A

Hence,the maximum current is0.005A.

Using the formula for maximum energy stored in the LC circuit, found the maximum current in the circuit.

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