Question: In Figure, light initially in material1refracts into material 2 , crosses that material, and is then incident at the critical angle on the interface between materials 2 and 3 . The indexes of refraction aren1=1.60,n2=1.40,andn3=1.20 .(a) What is angleθ ?(b) Ifθ is increased, is there refraction of light into material 3 ?

Figure:

Short Answer

Expert verified

Answer

  1. 26.80 is the angle.
  2. If θ is increased, there will be some transmission of light into material 3.

Step by step solution

01

Given 

n1=1.6n2=1.4n3=1.2

02

Understanding the concept

Using Snell’s law of refraction, we are able to calculate the value for θ.

Formula:

n1sinθ1=n2sinθ2

03

(a) Calculate the angle θ 

From the diagram, we can say that

θ2=90°-θCsinθ2=sin90-θCsinθ2=cosθCcosθC=1-sin2θC

We apply Snell’s law for material 1 and 2, and we get

n1sinθ=n2sinθ2

We have

sinθ2=cosθC

And

cosθC=1-sin2θCsinθ=n2n1×1-sin2θC

ForθC,we have

n2sinθC=n3sinθ3

Here,θ3=90°

sinθC=n3n2sinθ=n2n1×1-n3n22sinθ=1.41.6×1-1.21.42sinθ=0.875×0.515θ=sin-10.45θ=26.78°~26.8°

04

(b) If θ  is increased, find out if there is refraction of light into material 3

Increase in angle θ increases the angle with which the light is travelling from material 2 to material 3.

This will cause the angle to be greater than that of the critical angle.

From this, we can conclude that there will be some transmission of light into the third material.

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