Calculate the energy released in the fission reaction

U235+nCs141+Rb93+2n

Here are some atomic and particle masses.

U235235.04392uRb9392.92157uCs141140.91964un1.00866u

Short Answer

Expert verified

The released energy in fission reaction is 181. MeV.

Step by step solution

01

Given data

The mass of U235,mu=235.04392u

The mass of R93b,mRb=92.92157u

The mass of C147s,mCs=140.91963u

The mass of n,n=1.00866

02

Determine the energy released in the fission reaction.

The expression to calculate released energy is given as follows.

Q=-mc2Q=(mu+mn-mCs-mRb-2mn)c2 ...(i)

03

Calculate the released energy in the fission reaction.

Calculate the released energy.

Substitute 235.04392u for m2=92.92157u, for mRb,140.91963u for mCs,1.00866u forn and 931.5MeV/u forc2 into equation (i).

Q=(235.04392u+1.00866u-140.91963u-92.92157-2×1.00866u)×931.5MeV/uQ=(235.04392+1.00866-140.91963-92.92157-2.01732)×931.5MeVQ=0.19406×931.5MeVQ=181MeV

Hence the released energy in fission reaction is 181..MeV

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