The neutron generation time (see Problem 19) of a particular reactor is 1.3 ms .The reactor is generating energy at the rate of 1200.0 MW.To perform certain maintenance checks, the power level must temporarily be reduced to 350.00 MW. It is desired that the transition to the reduced power level take 2.6000 s. To what (constant) value should the multiplication factor be set to effect the transition in the desired time?

Short Answer

Expert verified

The multiplication factor is 0.99938409 .

Step by step solution

01

Given data

The initial power output of the reactor,

P0=1200.0MW

The final power output of the reactor,

P=350.00MW

The neutron generation time is,

tgen=1.3ms=1.3ms10-3s1ms=1.3×10-3s

The time for the power reduction

t=2.6000s

02

Find the multiplication factor

The power output of a reactor at time is given by

p=p0kt/tgen

Therefore, the multiplication factor can be expressed as

Ink=tgentInpp0=1.3×10-3s2.6000sIn350.00MW1200.0MWInK=-0.0006161k=e-0.0006161k=099938409

Therefore, the multiplication factor is 0.99938409.

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