A Carnot engine absorbs 52 kJas heat and exhausts 36 kJas heat in each cycle. (a) Calculate the engine’s efficiency and (b) Calculate the work done per cycle in kilojoules.

Short Answer

Expert verified
  1. The engine’s efficiency is 31%
  2. The work done per cycle in kilojoules is 16 kJ

Step by step solution

01

The given data

Heat extract from consuming fuel,QH=52kJ

Heat exhaustQL=36kJ

02

Understanding the concept of the Carnot engine

We use the formula of efficiency of Carnot’s heat engine to find the efficiency and work done per cycle.

Formulae:

The efficiency of a Carnot’s heat engine,

ε=1-QLQH=WQH (1)

03

(a) Calculation of efficiency of Carnot’s engine

The efficiency of Carnot’s engine using equation (1) is given as:

ε=1-36kJ52kJ=1-0.6923=0.307631%

Hence, the value of the efficiency of the engine is 31%

04

(b) Calculation of the work done per cycle

Using the same equation (1) for efficiency, the work done per cycle of the engine is given as:

W=εQH=0.3076×52kJ=15.99kJ16kJ

Hence, the value of the work done per cycle is 16 kJ

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