The table gives the initial lengths of three rods and the changes in their lengths when forces are applied to their ends to put them under strain. Rank the rods according to their strain, greatest first.

Short Answer

Expert verified

The greatest strain is for rods A and B, and strain in rod C is the least; thus, the rank is A = B > C .

Step by step solution

01

The given data

Initial length and the change in length are given for each rod A, B, and C.

02

Understanding the concept of strain

We use the definition of strain, which is a fractional increase in length, to calculate the required rank according to their strain measures.

Formulae:

The strain applied on a body due to a change in the length, Strain=LL (i)

03

Calculation of the rank of the rods according to their strain value

Using the given data in equation (i), the strain of rod A can be calculated as follows:

StrainA=L02L0

Using the given data in equation (i), the strain of the rod B can be calculated as follows:

StrainB=2L04L0=L02L0

Using the given data in equation (i), the strain of the rod C can be calculated as follows:

StrainB=4L010L0=2L05L0

Hence, the rank value according to their strain is A = B > C .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 73 kg man stands on a level bridge of length L. He is at distanceL/4 from one end. The bridge is uniform and weighs2.7 kN . What are the magnitudes of the vertical forces on the bridge from its supports at (a) the end farther from him and (b) the nearer end?

A ladder leans against a frictionless wall but is prevented from falling because of friction between it and the ground. Suppose you shift the base of the ladder toward the wall. Determine whether the following become larger, smaller, or stay the same (inmagnitude):

(a) the normal force on the ladder from the ground,

(b) the force on the ladder from the wall,

(c) the static frictional force on the ladder from the ground, and

(d) the maximum value Fs,max of the static frictional force.

Figure 12-85ashows details of a finger in the crimp holdof the climber in Fig. 12-50. A tendon that runs from muscles inthe forearm is attached to the far bone in the finger. Along the way, the tendon runs through several guiding sheaths called pulleys. The A2 pulley is attached to the first finger bone; the A4 pulley is attached to the second finger bone. To pull the finger toward the palm, the forearm muscles pull the tendon through the pulleys, much like strings on a marionette can be pulled to move parts of the marionette. Figure 12-85bis a simplified diagram of the second finger bone, which has length d. The tendon’s pull Fton the bone acts at the point where the tendon enters the A4 pulley, at distance d/3 along the bone. If the force components on each of the four crimped fingers in Fig. 12-50 are Fh=13.4 Nand Fv=162.4 N, what is the magnitude ofFt ? The result is probably tolerable, but if the climber hangs by only one or two fingers, the A2 and A4 pulleys can be ruptured, a common ailment among rock climbers.

In Fig. 12-72, two identical, uniform, and frictionless spheres, each of mass m, rest in a rigid rectangular container. A line connecting their centers is at45°to the horizontal. Find the magnitudes of the forces on the spheres from (a) the bottom of the container, (b) the left side of the container, (c) the right side of the container, and (d) each other. (Hint:The force of one sphere on the other is directed along the center–center line.)

Question: To crack a certain nut in a nutcracker, forces with magnitudes of at least 40 N must act on its shell from both sides. For the nutcracker of Figure, with distances L =12 cmand D = 2.6 cm , what are the force components F (perpendicular to the handles) corresponding to that 40 N?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free