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Chapter 12: Q16P (page 346)

Question: A uniform cubical crate is 0.750 m on each side and weighs 500 N . It rests on a floor with one edge against a very small, fixed obstruction. At what least height above the floor must a horizontal force of magnitude 350 N be applied to the crate to tip it?

Short Answer

Expert verified

Answer:

A horizontal force of 350 N must be applied at to tip the crate.

Step by step solution

01

Understanding the given information   

a=0.75mW=500NF=350N

02

Concept and formula used in the given question

Using the conditions for static equilibrium, you can write the equation for torque in terms of force and distance. Using this equation, you can solve for unknown height h. The equations used are given below.

Static equilibrium conditions:

∑Fx=0∑Fy=0∑τ=0

03

Calculation for the at least what height above the floor must a horizontal force of magnitude  350 N be applied to the crate to tip it  

Applying equilibrium condition:

∑τ=0W×a2-F×h=0500×0.752-350×h=0h=0.536m

Hence,a horizontal force of 350 N must be applied ath=0.536m to tip the crate.

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Most popular questions from this chapter

In Fig.12-48, the driver of a car on a horizontal road makes an emergency stop by applying the brakes so that all four wheels lock and skid along the road. The coefficient of kinetic friction between tires and road is 0.40.The separation between the front and rear axles is L=4.2 m, and the center of mass of the car is located at distance d=1.8 m behind the front axle and distanceh=0.75 m above the road. Theweight of car is 11 kN. Find the magnitude of (a) the braking acceleration of the car, (b) the normal force on each rear wheel, (c) the normal force on each front wheel, (d) the braking force on each rear wheel, and (e) the braking force on each front wheel. (Hint:Although the car is not in translational equilibrium, it isin rotational equilibrium.)

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