A uniform beam is 5.0 mlong and has a mass of 53 kg. In Fig. 12-74, the beam is supported in a horizontal position by a hinge and a cable, with angleθ=60°. In unit-vector notation, what is the force on the beam rom the hinge?

Short Answer

Expert verified

The force on the beam in unit vector notation,FP=(150N)i^+(260N)j^ .

Step by step solution

01

Understanding the given information

Mass, m=53 kg

Length of the beam,L=5.0 m

θ=60°

02

Concept and formula used in the given question

Using the condition for the static equilibrium, you can write the equation for forces for the given figure. In addition, the equation for the torque can be written about a pivot point. The equations are given below and can be solved for the unknown forces.

Condition of equilibrium,

τ=0Momentofforce=perpendiculardistance×Force

03

Calculation for theforce on the beam from the hinge

As we see the diagram, we can say that

Tsin60°×Lmg×(L2)=0Tsin60°=mg×(L2)LTsin60°=mg2sin60Tsin60°=300 N

As the system is in equilibrium, we can say

Fx=0Fy=0

So,

FPx=Tcosθ=(300N)(0.5)=150 NFPy=MgTsin60°=(519.4 ​N)(300N×0.8660)=260N

So, we get

FP=(150N)i^+(260N)j^

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free