Figure 12-19 shows an overhead view of a uniform stick on which four forces act. Suppose we choose a rotation axis through point O, calculate the torques about that axis due to the forces, and find that these torques balance. Will the torques balance if, instead, the rotation axis is chosen to be at

(a) point A(on the stick),

(b) point B(on line with the stick), or

(c) point C(off to one side of the stick)?

(d) Suppose, instead, that we find that the torques about point Odoes not balance. Is there another point about which the torques will balance?

Short Answer

Expert verified

a) The torques will balance about the rotation axis at point A.

b) The torques will balance about the rotation axis at point B.

c) The torques will balance about the rotation axis at point C.

d) The torque will not be balanced about any other point if it is not balanced about point O.

Step by step solution

01

The given data

The figure for the overhead view of a uniform stick on which four forces act is given.

02

Understanding the concept of torque

From the given condition for the net torque about axis O, we can conclude whether the stick is rotating or not. From this, we can determine whether the torques will balance or not at given points.

Formulae:

The value of the torque at equilibrium, τnet=0 (i)

03

a) Calculation to check whether the torques are balanced at point A

Since the torques about an axis at point O is balanced, the net torque is zero at point O. So, the stick is not rotating. It suggests that the net torque about any axis is zero according to the condition of equation (i).

Therefore the torques will balance about the rotation axis at points A, B and C.

Hence, the torques will be balanced on the stick at point A.

04

b) Calculation to check whether the torques are balanced at point B

From part (a), we can say that the torques will balance in line with the stick at point B.

05

c) Calculation to check whether the torques are balanced at point B

From part (a), we can say that the torques will balance off to one side of the stick at point C.

06

d) Calculation to check whether the torques will balance at any other point

Since torques about an axis at point O does not balance, the net torque is not zero at point O. So, the stick is rotating. It suggests that the net torque about any axis is not equal to zero, hence not in equilibrium according to the condition of equation (i).

Therefore the torques will not balance about the rotation axis at any point.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Figure 12-81 shows a 300 kg cylinder that is horizontal. Three steel wires support the cylinder from a ceiling. Wires 1 and 3 are attached at the ends of the cylinder, and wire 2 is attached at the center. The wires each have a cross-sectional area of2.00×106m2 . Initially (before the cylinder was put in place) wires 1 and 3 were2.0000 m2 long and wire 2 was 6.00 mmlonger than that. Now (with the cylinder in place) all three wires have been stretched. What is the tension in (a) wire 1 and (b) wire 2?

In Fig.12-48, the driver of a car on a horizontal road makes an emergency stop by applying the brakes so that all four wheels lock and skid along the road. The coefficient of kinetic friction between tires and road is 0.40.The separation between the front and rear axles is L=4.2m, and the center of mass of the car is located at distance d=1.8m behind the front axle and distanceh=0.75m above the road. Theweight of car is 11kN. Find the magnitude of (a) the braking acceleration of the car, (b) the normal force on each rear wheel, (c) the normal force on each front wheel, (d) the braking force on each rear wheel, and (e) the braking force on each front wheel. (Hint:Although the car is not in translational equilibrium, it isin rotational equilibrium.)

The leaning Tower of Pisa is 59.1 m high and 7.44 m in diameter. The top of the tower is displaced4.01 m from the vertical.Treat the tower as a uniform, circular cylinder. (a) What additional displacement, measured at the top, would bring the tower to the verge of toppling? (b) What angle would the tower then make with thevertical?

In Fig. 12-67a, a uniform40.0kgbeam is centered over two rollers. Vertical lines across the beam mark off equal lengths. Two of the lines are centered over the rollers; a 10.0kgpackage of tamales is centered over roller B.What are the magnitudes of the forces on the beam from (a) roller Aand (b) roller B? The beamis then rolled to the left until the right-hand end is centered over roller B(Fig. 12-67b).What now are the magnitudes of the forces on the beam from (c) roller Aand (d) roller B? Next, the beam is rolled to the right. Assume that it has a length of 0.800 m. (e) what horizontal distance between the package and roller Bputs the beam on the verge of losing contact with rollerA?

In Fig. 12-20, a stationary 5 kg rod ACis held against a wall by a rope and friction between rod and wall. The uniform rod is 1 m long, and angle

(a) If you are to find the magnitude of the force T
on the rod from the rope with a single equation, at what labeled point should a rotation axis be placed? With that choice of axis and counter-clockwise torques positive,

what is the sign of

(b) the torqueτwdue to the rod’s weight and

(c) the torqueτrdue to the pull on the rod the rope?

(d) Is the magnitude of τrgreater than, less than, or equal to the magnitude of τw?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free