Suppose that your body has a uniform density of0.95times that of water. (a) If you float in a swimming pool, what fraction of your body's volume is above the water surface? Quicksand is a fluid produced when water is forced up into sand, moving the sand grains away from one another so they are no longer locked together by friction. Pools of quicksand can form when water drains underground from hills into valleys where there are sand pockets. (b) If you float in a deep pool of quicksand that has a density 1.6times that of water, what fraction of your body's volume is above the quicksand surface? (c) Are you unable to breathe?

Short Answer

Expert verified

Answer:

(a) Fraction of the body's volume above the water surface $=0.05$

(b) Fraction of the body's volume above the quicksand surface $=0.41$

(c) Yes, we can breathe though we are stuck in quicksand.

Step by step solution

01

Listing the given quantities

  • The density of the body ρb=0.95times the density of the water ρw.
  • The density of the quicksand ρq=6times the density of the water ρw.
02

Understanding the concept of buoyant force

By equating the buoyant force and weight of the fluid displaced by the body, we can find the relation Vfρf=Vbρb. Using this, we can find the fraction of the body's volume above the fluid surface.

Formula:

Fraction =Vb-VfVb

=1-VtVb

Vfρf=Vbρb

03

(a) Calculation of fraction of the body's volume above the water surface

Fraction =1-VfVb (1)

Buoyant force Fb=weight of the fluid displaced by the body Fw

Vfρfg=Vbρbg

Rearranging the equation,

VfVb=ρbρf

Using in above equation (1),

Fraction =1-ρbρf

=1-0.95ρWρw

=1-0.05

=0.05

Fraction of the body's volume above the water surface is0.05

04

(b) Calculation of fraction of the body's volume above the quicksand surface

Fraction =1-ρbρq

Using given values,

Fraction =1-0.95ρw1.6ρw

=1-0.593375

=0.4062

0.41

Fraction of the body's volume above the quicksand surface is0.41

05

(c) Explanation for the calculation

From part b,0.41of the total human body will be above the quicksand. As the human body is less dense than quicksand, a person would sink to their chest and then float. Hence a person can breathe.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Figure 14-48 shows an iron ball suspended by thread of negligible mass from an upright cylinder that floats partially submerged in water. The cylinder has a height of6.00 cm, a face area of12.0cm2on the top and bottom, and a density of 0.3g/cm3, and 2.00 cmof its height is above the water surface. What is the radius of the iron ball?

A garden hose with an internal diameter of 1.9cmis connected to a (stationary) lawn sprinkler that consists merely of a container with 24holes, each 0.13cmin diameter. If the water in the hose has a speed of 0.91m/s, at what speed does it leave the sprinkler holes?

Figure 14-21 shows four situations in which a red liquid and a gray liquid are in a U-tube. In one situation the liquids cannot be in static equilibrium. (a) Which situation is that? (b) For the other three situations, assume static equilibrium. For each of them, is the density of the red liquid greater than, less than, or equal to the density of the gray liquid?

Flotation device is in the shape of a right cylinder, with a height of 0.500mand a face area of 4.00m2on top and bottom, and its density is localid="1657554653816" 0.400 times that of fresh water. It is initially held fully submerged in fresh water, with its top face at the water surface. Then it is allowed to ascend gradually until it begins to float. How much work does the buoyant force do on the device during the ascent?

(a) For seawater of density 1.03 g/cm3, find the weight of water on top of a submarine at a depth of 255mif the horizontal cross-sectional hull area is 2200.0m2. (b) In atmospheres, what water pressure would a diver experience at this depth?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free