A filing cabinet weighing 556 Nrests on the floor. The coefficient of static friction between it and the floor is 0.68, and the coefficient of kinetic friction is 0.56. In four different attempts to move it, it is pushed with horizontal forces of magnitudes (a) 222 N, (b) 334 N, (c) 445 N, and (d) 556 N. For each attempt, calculate the magnitude of the frictional force on it from the floor. (The cabinet is initially at rest.) (e) In which of the attempts does the cabinet move?

Short Answer

Expert verified

(a) The magnitude of the frictional force is f = 222 N .

(b) The magnitude of the frictional force is f = 334 N .

(c) The magnitude of the frictional force is f = 311 N .

(d) The magnitude of the frictional force is f = 311 N .

Step by step solution

01

Given data:

Weight of the cabinet, W = 556 N

Coefficient of static friction between the cabinet and the floor,μs=0.68

Coefficient of kinetic friction,μk=0.56

02

Understanding the concept:

In order to move a filing cabinet, the force applied must be able to overcome

the frictional force.

Apply Newton’s second law

Fpush-f=Fnet=ma

If you find the applied force Fpushto be less than fs,max, the maximum static frictional force, our conclusion would then be “no, the cabinet does not move” (which means is actually zero and the frictional force is simply f=Fpush). On the other hand, if you obtain a > 0 then the cabinet moves (so f=fk).

For fs,maxand fkuse Eq. 6-1 and Eq. 6-2 (respectively), and in those formulas set the magnitude of the normal force to the weight of the cabinet.

03

Calculate the maximum static friction and kinetic friction:

The maximum static frictional force is,

fs,max=μsFN

Here, the weight of the cabinet will be balanced by the normal force. Therefore,

fs,max=μsW

And the kinetic frictional force is,

fk=μkfk=μkW=0.56556N=311N

04

(a) Define the magnitude of the frictional force with horizontal force of magnitude 222 N :

Calculate the magnitude of the frictional force on the cabinet from the floor when it is pushed with horizontal force of magnitudes, which is,

.Fpush=222N

Here, the magnitude of the horizontal pushing force is less than the maximum static force. Therefore,

Fpush<fs,max222N<378N

Hence, the cabinet does not move. So, acceleration of the cabinet will be zero.

a=0m/s2

The frictional force is,

Fpush-f=ma=m0m/s2=0f=Fpush=222N

Here, the magnitude of the frictional force between the carbonate and the floor is f = 222N .

05

(b) Determine the magnitude of the frictional force with horizontal force of magnitude 334 N :

Calculate the magnitude of the frictional force on the cabinet from the floor when it is pushed with horizontal force of magnitudes, which is

Fpush=334N

Here, the magnitude of the horizontal pushing force is less than the maximum static force. Thus,

Fpush<fs,max334N<378N

Hence, the cabinet does not move. So, acceleration of the cabinet will be zero.

a=0m/s2

The frictional force is,

Fpush-f=ma=0f=Fpush=334N

06

(c) Define the magnitude of the frictional force with horizontal force 445 N :

Calculate the magnitude of the frictional force on the cabinet from the floor when it is pushed with horizontal force of magnitudes, which is,

Fpush=445N.

Here, the magnitude of the horizontal pushing force is less than the maximum static force. Thus,

Fpush>fs,max445N>378N

Hence, the cabinet will move. So, the frictional force will be he kinetic friction. Hence, the friction force in this case between the cabinet and the floor is,

f=Fk=311N

07

(d) The magnitude of the frictional force with horizontal force 556 N :

Calculate the magnitude of the frictional force on it from the floor when it is pushed with horizontal force of magnitudes, which is,

Fpush=556N.

Again, you have

Fpush>fs,max556N>378N

Which means the cabinet moves.

Hence, the cabinet will move. So, the frictional force will be he kinetic friction. Hence, the friction force in this case between the cabinet and the floor is,

f=fk=311N

08

(e) Find out in which of the attempts does the cabinet move:

As in part (c) and (d) you haveFpush>fs,maxwhich means the cabinet moves.

Hence, the cabinet moves in (c) and (d).

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