Certain neutron stars (extremely dense stars) are believed to be rotating at about1rev/s. If such a star has a radius of20 km, what must be its minimum mass so that material on its surface remains in place during the rapid rotation?

Short Answer

Expert verified

Mass of the material on the surface of the neutron star is5×1024 kg

Step by step solution

01

The given data 

1) Frequency of rotation of neutron star is

f=1revs

2)Radius of neutron star isR=20000 m

02

Understanding the concept of Differential acceleration equation 

We use the acceleration difference equation to find the mass of the material on the surface of the neutron star.

Formula:

Acceleration difference equation due to revolution,g=agω2R ... (i)

03

Calculation of the mass of the material 

From equation (i), we can get

ag=GMR2

To stay stationary on the surface of the neutron star, forces should be balanced so that, g= 0.

Hence substituting g=0 in equation (i), we get

0=GMR2ω2RGMR2=ω2RM=ω2R3G

Substituting the values ofω=2πfand R=20000 mwe get,

M=2π×1  revs220000  m36.67×1011  Nm2/kg2=4.7×10245×1024 kg

The mass of the material on the neutron star should be5×1024 kg.

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