The Sun’s center is at one focus of Earth’s orbit. How far from this focus is the other focus,

(a) in meters and

(b) in terms of the solar radius,6.96×108m? The eccentricity is0.0167, and the semimajor axis is1.50×1011m.

Short Answer

Expert verified
  1. Distance between two foci of earth’s orbit in meters5.0×109m.
  2. Distance between two foci of earth’s orbit in terms of the solar radius Rsis 7.2×Rs.

Step by step solution

01

Step 1: Given

Rs=6.96×108m

Eccentricity (e)=0.0167

Semi major axis(a)=1.50×1011m

02

Determining the concept

As the distance between the focus of the ellipse and the center of the ellipse iseccentricity × semi-major axis, calculate the distance between the two foci in meters of earth’s orbit both in meters and in terms of the radius of the sun.

The formula is as follows:

Distance (focus and center of the ellipse) = eccentricity × semi-major axis

03

(a) Determining the distance between two foci of the earth’s orbit in meters

From the diagram,

DistanceF1andF2=((a×e)+(a×e))=((0.0167×1.50×1011m)+(0.0167×1.50×1011m))=(2.5×109m)+(2.5×109m)=5.0×109m

Hence, the distance between two foci of the earth’s orbit is in meters 5.0×109m.

04

(b) Determining the distance between two foci of the earth’s orbit in terms of the solar radius Rs

Now,

DistanceF1andF2=5.0×109m

Multiply and divide to the right-hand side by the radius of the sunRs,

DistanceF1andF2=5.0×109m×RsRs=5.0×109m×Rs6.96×108m=7.2×Rs

Hence, the distance between two foci of the earth’s orbit in terms of the solar radiusRsis7.2×Rs.

Therefore, using the formula for the distance between the focus of the ellipse and the center of the ellipse, the distance between the two foci of the earth can be found.

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