A satellite orbits a planet of unknown mass in a circle of radius 2.0×107m. The magnitude of the gravitational force on the satellite from the planet is F=80N.

(a) What is the kinetic energy of the satellite in this orbit?

(b) What would F be if the orbit radius were increased to3.0×107m ?

Short Answer

Expert verified
  1. Kinetic energy of the satelliteK=8.0×108J
  2. Gravitational force when the orbit radius is increased to 3×107m is (F2)=35.5N

Step by step solution

01

Listing the given quantities

r1=2×107m

F1=80N

r2=3×107m

02

Understanding the concept of gravitational force and kinetic energy

Using the given gravitational force and kinetic energy formula, we can findthekinetic energy of the satellite (Ks ). Using F1r2,we can find gravitational forceF2 when the radius is increased to 3×107 m

Formula:

K=GMm2(r)

F=GMmr2

03

(a) Calculation of kinetic energy of satellite  

K=GMm2(r1)

F1=GMmr12

F1×r1=GMmr1

Using this in kinetic energy equation (1),

K=12F1×r1=1280 N×2×107 m=8.0×108J

04

(b) Calculation of Gravitational force when the orbit radius is increased 

F11r12F21r22F1F2=r22r12F1F2=(2×107 m)2(3×107 m)2F1F2=49

Using the given value ofF1

F2=4×80 N9=35.5N

Gravitational force when the orbit radius is increased to 3×107misF2=35.5N

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