A cheese enchilada is4.00cmin front of a converging lens. The magnification of the enchilada is-2.00. What is the focal length of the lens?

Short Answer

Expert verified

Focal length of the lens isf=2.67cm

Step by step solution

01

Listing the given quantities 

m=-2.0p=4.0cm

02

Understanding the concepts of magnification

We will use the relation between object distance, image distance, and focal length for the converging lens.

Formula:

1p+1i=1f

Magnification

m=-ip=HiHp

03

Calculation of the focal length of the lens

We have magnification as

m=-ip2p=i

Distance of the object isi=8.0cm

Now, to find focal length, we will use the following relation:

1f=1p+1if=10.375=2.67cm

Focal length of the lens isf=2.67cm

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Most popular questions from this chapter

50 through 57 55, 57 53 Thin lenses. Object Ostands on the central axis of a thin symmetric lens. For this situation, each problem in Table 34-6 gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find (a) the image distance iand (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real (R) or virtual (V) , (d) inverted (I)from object O or non inverted (NI) , and (e) on the same side of the lens as object Oor on the opposite side.

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