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Chapter 34: Q4Q (page 1037)

A penguin waddles along the central axis of a concave mirror, from the focal point to an effectively infinite distance. (a) How does its image move? (b) Does the height of its image increase continuously, decrease continuously, or change in some more complicated manner?

Short Answer

Expert verified

(a) The penguin’s image moves from infinity to the focal point.

(b) The height of the penguin’s image decreases continuously.

Step by step solution

01

Given data

A penguin waddles along the central axis of a concave mirror from the focal point to an effectively infinite distance.

02

Understanding the concept of optical image

Using the characteristics of the image formed due to a concave mirror when an object is placed at a focal point and an infinite distance from the focal point, we can answer the above questions.

03

(a) Calculation of the reason of movement of the image

The penguin’s image moves from infinity to the focal point since it waddles along the central axis of a concave mirror, from the focal point to an effectively infinite distance.

04

(b) Calculation of the change in height of the image

The height of the penguin’s image decreases continuously since it waddles along the central axis of a concave mirror, from the focal point to an effectively infinite distance.

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Most popular questions from this chapter

An object is placed against the center of a concave mirror and then moved along the central axis until it is 5.0 m from the mirror. During the motion, the distance |i|between the mirror and the image it produces is measured. The procedure is then repeated with a convex mirror and a plane mirror. Figure 34-28 gives the results versus object distance p. Which curve corresponds to which mirror? (Curve 1 has two segments.)

32 through 38 37, 38 33, 35 Spherical refracting surfaces. An object Ostands on the central axis of a spherical refracting surface. For this situation, each problem in Table 34-5 refers to the index of refraction n1where the object is located, (a) the index of refraction n2on the other side of the refracting surface, (b) the object distancep, (c) the radius of curvature rof the surface, and (d) the image distance i. (All distances are in centimeters.) Fill in the missing information, including whether the image is (e) real (R)or virtual (V)and (f) on the same side of the surface as the object Oor on the opposite side.

50 through 57 55, 57 53 Thin lenses. Object Ostands on the central axis of a thin symmetric lens. For this situation, each problem in Table 34-6 gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find (a) the image distance iand (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real (R) or virtual (V) , (d) inverted (I)from object O or non inverted (NI) , and (e) on the same side of the lens as object Oor on the opposite side.

An object is 20cmto the left of a thin diverging lens that has a 30cmfocal length. (a) What is the image distance i? (b) Draw a ray diagram showing the image position.

a real inverted imageof an object is formed by a particular lens (not shown); the object–image separation is, measured along the central axis of the lens. The image is just half the size of the object. (a) What kind of lens must be used to produce this image? (b) How far from the object must the lens be placed? (c) What is the focal length of the lens?
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